asked 132k views
5 votes
A digital system has a clock generator that produces pulses at a frequency of 80MHz. Design a circuit that provides a clock with a cycle time of 50 ns.

asked
User Feanaro
by
8.0k points

1 Answer

0 votes

Final answer:

To design a circuit that provides a clock with a cycle time of 50 ns from an 80MHz clock generator, one needs to use a frequency divider that divides the frequency by 4, giving a resultant frequency of 20MHz.

Step-by-step explanation:

The question involves designing a circuit that will provide a clock signal with a cycle time of 50 nanoseconds (ns), given an initial clock generator frequency of 80MHz.

To achieve a 50 ns cycle time, you need a clock frequency of 20MHz because the cycle time (T) is the reciprocal of the frequency (f), or T = 1/f. Since 1/(20MHz) is 50 ns, we need to divide the 80MHz clock by a factor of 4. This can be accomplished using a frequency divider, which is a digital circuit that takes an input clock frequency and outputs a clock frequency that is a lower division of the input.

A simple way to create a frequency divider by 4 is to use a counter that counts two bits (since 22 = 4). Each time the counter goes through its full range, it will output a single pulse, effectively dividing the input clock frequency by 4. Using such a frequency divider, you can convert the 80MHz input to the required 20MHz output, which corresponds to the 50 ns cycle time needed for the clock.

answered
User Dupersuper
by
7.6k points