Final answer:
The instantaneous velocity at t=1 is found by taking the derivative of the position function s(t)=6t²+5t+4, which results in a velocity function v(t)=12t+5. Substituting t=1 into the velocity function gives an instantaneous velocity of 17 m/s.
Step-by-step explanation:
To find the instantaneous velocity when t=1 for the given position function s(t)=6t²+5t+4, we must take the derivative of the position function with respect to time, which will give us the velocity function.
The derivative of s(t) is v(t)=ds/dt=12t+5. Substituting t=1 into v(t), we get v(1)=12(1)+5=17. Therefore, the instantaneous velocity at t=1 is 17 m/s.