Final answer:
To sketch the Bode plots for the given transfer function, calculate the magnitude and phase of the transfer function for different frequencies and plot them on logarithmic scales.
Step-by-step explanation:
Bode plots are used to represent the frequency response of a system. In this case, we have the transfer function H(ω) = 0.2 (10 + jω )/jω (2 +jω ). To sketch the Bode plots, we need to calculate the magnitude and phase of the transfer function for different frequencies.
First, let's calculate the magnitude. The magnitude can be found by taking the absolute value of the transfer function. So, |H(ω)| = |0.2 (10 + jω )/jω (2 +jω )| . Next, we need to calculate the phase. The phase can be found by taking the argument of the transfer function. So, ∠H(ω) = arg(0.2 (10 + jω )/jω (2 +jω )).
Once we have the magnitude and phase, we can plot the Bode plots. The magnitude plot is a logarithmic scale that shows the amplitude of the transfer function in decibels. The phase plot shows the phase shift of the transfer function in degrees.