Question

For f (x) = 3x +1 and g(x) = x2 - 6, find (ff + g)(x).

Answer 1

Given:

The two functions are

`f(x)=3x+1`

`g(x)=x^2-6`

To find:

The function (f+g)(x).

Solution:

We know that,

`(f+g)(x)=f(x)+g(x)`

Putting the values of given functions, we get

`(f+g)(x)=3x+1+x^2-6`

`(f+g)(x)=x^2+3x+(1-6)`

`(f+g)(x)=x^2+3x-5`

Therefore, the required function is
`(f+g)(x)=x^2+3x-5`.