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1 vote
Complete the statement about how you could solve the equation 2c−3=2(6−c)+ 7c .

Distribute and collect like terms on each side, , 1 of 3.
Select Choice
a.12 from each side, , 2 of 3.
b.2c from each side, then , 3 of 3.
c.each side by 3.

asked
User Fuv
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8.5k points

1 Answer

5 votes

Final answer:

To solve the equation 2c−3=2(6−c)+7c, you must distribute the 2, combine like terms, subtract 2c from each side, and finally, subtract 12 and divide by 3 to isolate and solve for c.

Step-by-step explanation:

To solve the equation 2c−3=2(6−c)+7c, we need to distribute and collect like terms on each side. Let's break down the steps involved in solving this equation:

  1. Distribute the 2 in 2(6−c) to obtain 12 - 2c.
  2. Combine like terms on each side. On the left, we have 2c, and on the right, we have −2c + 7c. Adding −2c and 7c gives us 5c.
  3. The equation now looks like 2c - 3 = 12 + 5c. To isolate c, subtract 2c from each side, leading to -3 = 12 + 3c.
  4. Finally, subtract 12 from each side to obtain −3 - 12 = 3c, which simplifies to −15 = 3c.
  5. Divide each side by 3 to find the value of c, resulting in c = −5.

After finding the value for c, we should check the answer to ensure it is reasonable by plugging it back into the original equation.

answered
User Chris Sprague
by
8.0k points
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