asked 90.3k views
5 votes
The height of a golf ball hit into the air is modeled by the equation h=-16t^2+48t, where H represents the height, in feet, and he represents the number of seconds that have passed since the ball was hit. What is the height of the ball after two seconds?

asked
User Osorio
by
8.3k points

1 Answer

5 votes

Answer:

Height = 32 feet.

Explanation:

Substituting for t in the equation:

t = 2 so,

h = -16(2)^2 + 48(2)

= -64 + 96

= 32 feet.

answered
User Meric Ozcan
by
7.9k points
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