Question

John’s float goes from point a to B then to see then to Dee and back to a. If he repeats this route twice, the total distance that his float travels is how many kilometers?

(A) 2 x (distance from A to B + distance from B to C + distance from C to D + distance from D to A)
(B) 4 x (distance from A to B + distance from B to C + distance from C to D + distance from D to A)
(C) 1/2 x (distance from A to B + distance from B to C + distance from C to D + distance from D to A)
(D) None of the above

Answer 1

The total distance that John's float travels in two repetitions of the route is 2 times the sum of the distances for each segment of the route from A to B, B to C, C to D, and D back to A.

Step-by-step explanation:

To find the total distance that John's float travels in two repetitions of the route, we need to add up the distances for each segment of the route. Let's call the distance from A to B DAB, from B to C DBC, from C to D DCD, and from D back to A DDA. The total distance is then given by 2 x (DAB + DBC + DCD + DDA). Therefore, the correct option is (A) 2 x (distance from A to B + distance from B to C + distance from C to D + distance from D to A).