Final answer:
The question involves solving for 'x' given two equations with 'm' and 'x'. Relevant information to provide a specific answer is missing, but the usual method involves expressing 'm' from one equation, substituting into the other, and solving the resultant quadratic equation for 'x'.
Step-by-step explanation:
The student's question is regarding the solution for x in two equations that are given: m/2 = (4x + 5) and m4 = (x² - 27). The provided information does not include a direct way to solve these equations, and it seems there might be some confusion with the question as it is presented with irrelevant data. Nevertheless, I can guide the student on how to approach the problem using algebraic methods.
To solve for x, we could first express m from one of the equations and then substitute it into the other. However, without additional context or the correct equations that are to be solved, I am unable to provide a specific solution to this problem. Typically, one would isolate m in one equation and substitute it into the second equation, then solve the resulting quadratic equation for x using the quadratic formula if necessary.
As an example, if the equations were m/2 = 4x + 5 and m = x² - 27, we could find m from the second equation and substitute it into the first, leading to a quadratic in x that can be solved. The correct approach is dependent on the accurate equations, which needs to be clarified.