Question

You have 12.0 mL of a 3.00 M sulfuric acid solution. This solution is diluted to a new volume of 47.0 mL. What is the new molarity of the solution after dilution?

Answer 1

The new molarity of the sulfuric acid solution after dilution is 0.765 M.

Step-by-step explanation:

To find the new molarity of the sulfuric acid solution after dilution, we can use the formula:

M1V1 = M2V2

Where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume.

Plugging in the values, we have:

(3.00 M)(12.0 mL) = (M2)(47.0 mL)

Solving for M2, we get the new molarity of the solution after dilution as 0.765 M.