Question

Given that loga2=0.3010 and loga3= 0.4771 find loga72

Answer 1

`log_(a)(72) = log_(a)(8 * 9) = log_(a)( {2}^(3) {3}^(2) ) =`

`log_(a)( {2}^(3) ) + log_(a)( {3}^(2) ) =`

`3 log_(a)(2) + 2 log_(a)(3) =`

`3(.3010) + 2(.4771) = 1.8572`