The value of the function f(5) for f(x) = 1/2(3)ˣ + 2 is DNE
How to evaluate the function
From the question, we have the following parameters that can be used in our computation:
f(x) = 1/2(3)ˣ + 2
Also, we have the domain to be
x ≤ 4
This means that we can not calculate the function f(5)
This is so because the value of x in f(5) is out of the domain of the function f(x)
Hence, the function is DNE at x = 5
Question
f(x) = 1/2 * (3) ^ x + 2 when x <= 4
Calculate f(5)