Question

A charge of +0.18 C is moved from a position where the electric potential is 20 V to a position where the electric potential is 50 V. What is the change in potential energy o the charge associated with this change in position?

Answer 1

Step-by-step explanation:

The change in potential energy (ΔPE) of a charge when it is moved between two positions with different electric potentials can be calculated using the formula:

ΔPE = q * ΔV

Where ΔPE is the change in potential energy, q is the charge, and ΔV is the change in electric potential.

Given:

Charge (q) = +0.18 C

Change in electric potential (ΔV) = 50 V - 20 V = 30 V

Substituting the values into the formula:

ΔPE = (+0.18 C) * (30 V)

Calculating the product:

ΔPE = 5.4 J

Therefore, the change in potential energy of the charge associated with this change in position is 5.4 Joules.