Question

Which elements of the set {6, 0, √2, √64, &7, -146} are also integers?

Answer 1

{6,0,sqrt(64),7,-146}

Step-by-step explanation:

we take a look at each one of them.

6 is an integer.

0 is an integer.

sqrt(2) is irrational.

sqrt(64) is equal to 8, an integer.

7 is an integer.

-146 is an integer.

so, all are integers apart from sqrt(2)

Answer 2

To determine which are integers, we look for whole numbers without fractions or decimals. Integers within the set {6, 0, √2, √64, &7, -146} are 6, 0, the square root of 64 (which is 8), and -146.

Step-by-step explanation:

The student is asking about identifying integers within a given set. The elements of the set are {6, 0, √2, √64, &7, -146}. To determine which are integers, we look for whole numbers without fractions or decimals.

• 6 is an integer because it is a whole number.
• 0 is also an integer as it represents a whole number with no fractional or decimal part.
• √2 is not an integer; it is an irrational number (approximately 1.414).
• √64 is an integer because the square root of 64 is 8, which is a whole number.
• &7 appears to be a typographical error but is not a recognizable integer.
• -146 is an integer as it represents a whole negative number.

The integers in the set are therefore 6, 0, √64 (which is 8), and -146.