Question

Lithium and phosphorus react to lithium phosphide. How many mole of P2 are needed to react with 0.710mol of lithium?

Answer 1

To react with 0.710 mol of lithium, 0.2366 mol of P2 is needed.

Step-by-step explanation:

To determine the number of moles of P2 needed to react with 0.710 mol of lithium, we need to establish a balanced chemical equation for the reaction. The balanced equation is:

6Li + P4 → 2Li3P

From the balanced equation, we can see that 1 mole of P4 reacts with 2 moles of Li3P. Therefore, to calculate the moles of P2 needed, we can use the mole ratio:

(0.710 mol Li) * (1 mol P4 / 6 mol Li) * (2 mol P2 / 1 mol P4) = 0.2366 mol P2

So, 0.2366 mole of P2 is needed to react with 0.710 mole of lithium.