Question

Using the discriminatory determine how many real solutions this quadratic equation has 2x^2-5x+3=0

Answer 1

Step-by-step explanation:

D = b^2 — 4ac

D = (-5)² - 4*2*3 = 1.

D>0, so the real solutions = 2.

Answer 2

2 real solutions

Step-by-step explanation:

For discriminant of equation ax^2 + bx + c, if:

b^2 - 4ac > 0 then it have 2 real solutions

b^2 - 4ac = 0 then it has 1 real solution

b^2 - 4ac < 0 then it has no real solution

Check the discriminant:

• Equation: 2x^2-5x+3=0

⇒ (-5)^2 - 4(2)(3) = 25 - 24 = 1

As, 1 > 0 so it shows the equation has 2 real solutions.