Final Answer:
The community with greater species richness is Community A, while Community B exhibits greater species evenness. In terms of species diversity using the Shannon index, Community A has higher diversity.
Step-by-step explanation:
In ecological terms, species richness refers to the total number of different species present in a community. Community A has a higher species richness, as it has more distinct species. On the other hand, species evenness considers how evenly individuals are distributed among the different species. Community B has greater species evenness, indicating a more balanced distribution of individuals among its species.
To calculate the Shannon index for species diversity, we use the formula:
![\[H' = - \sum_(i=1)^(S) p_i \ln(p_i)\]](https://img.qammunity.org/2024/formulas/biology/high-school/s4agde71i92mzy2qr6817uc8sxdy8aif2i.png)
where H' is the Shannon index, S is the number of species, and pi is the proportion of individuals belonging to the \(i\)-th species. In Community A, if we have species a, b, and c with proportions pa, pb and
respectively, the Shannon index would be calculated by substituting these values into the formula. The higher the Shannon index, the greater the species diversity.
In summary, Community A has higher species richness, while Community B demonstrates greater species evenness. The Shannon index calculation further supports that Community A exhibits higher species diversity due to a more equitable distribution of individuals among its species.
Complete question:
which community has greater species richness? which community has greater species evenness? which community has higher species diversity using the shannon index?