Question

14a^2+4a+1=4a^2 solve using the quadratic formula

Answer 1

10a² + 4a + 1 = 0

a = (-4 ± √(4² - 4(10)(1)))/20

= (-4 ± √-24)/20

= (-4 ± 2i√6)/20

= (-2 ± i√6)/10

= (-1/5) ± (1/10)i√6