asked 80.1k views
1 vote
Drew had $50 to spend at the fair. If the admission to the fair is $8 and the rides

cost $1.50 each. What is the greatest number of rides Drew can go on?
Write an inequality to represent Drew's situation?
a)
b)
How many rides can Drew go on?
c) Graph the solution on a number line

1 Answer

2 votes

Answer:

Below in bold.

Explanation:

Let greatest number of rides be x then:

a) 8 + 1.5x ≤ 50

b) 8 + 1.5x ≤ 50

1.5x ≤ 50 - 8

1.5x ≤ 42

x ≤ 28.

So he can go on 28 rides maximum.

c) __________________

0 ^

Filled dot at x = 28.

answered
User Riezebosch
by
7.8k points
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