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(c)_Differentiate (x+2) (x+3) (x-2)(x-3) w.r.t. x.​

(c)_Differentiate (x+2) (x+3) (x-2)(x-3) w.r.t. x.​
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(c)_Differentiate (x+2) (x+3) (x-2)(x-3) w.r.t. x.​

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User PFranchise
by
8.4k points

1 Answer

7 votes

Answer:

Explanation:


y=(x+2)(x+3)(x-2)(x-3)\\\\y=(x^2-4)(x^2-9)\\\\y'=2x*(x^2-9)+2x*(x^2-4)\\\\y'=2x^3-18x+2x^3-8x\\\\y'=4x^3-26x\\

answered
User Tharif
by
8.7k points
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