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3 votes
The coefficient of 1/x in the expansion of (1+2/x)^3

asked
User Dasunx
by
8.5k points

2 Answers

2 votes

Answer:

6

Explanation:


\left(1+(2)/(x)\right)^3=\sum_(k=0)^3\binom{3}{k}\cdot 1^(3-k)\cdot\left((2)/(x)\right)^k\\ k=1\Rightarrow\binom{3}{1}\cdot 1^(3-1)\cdot\left((2)/(x)\right)^1=(6)/(x)

answered
User Naltatis
by
8.0k points
4 votes

Answer:

Answer 6

Explanation:

We are going to use the formula :


(a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\(1+(2)/(x))^3 =1^3+3*1^2*(2)/(x) +3*1*((2)/(x) )^2+((2)/(x))^3\\=1+(6)/(x) +(12)/(x^2) +(8)/(x^3) \\

answered
User DBAndrew
by
8.2k points

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