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5 votes
Find the 41st term in the given arithmetic sequence: 12, 19, 26,...

asked
User Nonna
by
7.9k points

1 Answer

7 votes

Answer:

292

Explanation:

The first term of the AP is 12 and the common difference is 19-12=7

The 41 th term is:


u_(41)=u_1+40*7=12+280=292\\

answered
User Pratik Bhatt
by
8.6k points

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