Question

The price of Stock A at 9 A.M. was $12.73.

Since then, the price has been increasing at the rate of $0.06 per hour.
At noon, the price of Stock B was $13.48. It begins to decrease at the rate of $0.14 per hour. If the stocks continue to increase and decrease at the same rates, in how many hours will the prices of the stocks be the same?

Answer 1

Explanation:

To find the number of hours it takes for the prices of Stock A and Stock B to be the same, we can set up equations for their respective prices at a given time.

For Stock A:

- The initial price at 9 A.M. is $12.73.

- The price increases at a rate of $0.06 per hour.

So, the equation for the price of Stock A after "h" hours would be:

Price of Stock A = $12.73 + ($0.06 * h)

For Stock B:

- The price at noon is $13.48.

- The price decreases at a rate of $0.14 per hour.

The equation for the price of Stock B after "h" hours would be:

Price of Stock B = $13.48 - ($0.14 * h)

To find the number of hours when the prices of Stock A and Stock B are the same, we can set the two equations equal to each other:

$12.73 + ($0.06 * h) = $13.48 - ($0.14 * h)

Simplifying the equation, we get:

$0.20 * h = $0.75

To solve for "h", divide both sides of the equation by $0.20:

h = $0.75 / $0.20

Calculating the result:

h = 3.75

Therefore, it will take approximately 3.75 hours for the prices of Stock A and Stock B to be the same.