Question

3 the width of a rectangle is four inches less than its length. the perimeter of the rectangle is 52 inches. find the two dimensions.

Answer 1

x= width

x+4 = length

perimeter of a rectangle =2(length+width)

52=2(x+x+4)

52 =4x+8

-4x=8-52

4x=44

x=11

width = 11 inches

length = 15 inches