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How many grams of iron (III) oxide are needed to produce 86.0 g of iron metal?

How many grams of iron (III) oxide are needed to produce 86.0 g of iron metal?
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How many grams of iron (III) oxide are needed to produce 86.0 g of iron metal?

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User Swordslayer
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1 Answer

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Answer: 122.9 g

Explanation: Fe2O3 mw = 160 of which 112 is Fe

to get 86 g Fe, 86*160/112 g oxide

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User Michael Born
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