Question

16. How much 0.5M Ca(OH)2 do you need to neutralize 4L of 2.5M HC1?

Given: C₂V₁-C₂Vb
a)0.5L b)2L c)5L d)10L e)20L

Answer 1

To neutralize 4L of 2.5M HCl, you would need 10L of 0.5M Ca(OH)2.

Step-by-step explanation:

To determine the amount of 0.5M Ca(OH)2 needed to neutralize 4L of 2.5M HCl, we can use the formula C₂V₁ = C₂Vb. Here, C₂ is the concentration of Ca(OH)2, V₁ is the volume of Ca(OH)2, Cb is the concentration of HCl, and Vb is the volume of HCl.

First, let's substitute the given values into the formula:

C₂V₁ = C₂Vb

0.5M * V₁ = 2.5M * 4L

Now we can solve for V₁:

V₁ = (2.5M * 4L) / 0.5M

V₁ = 10L

Therefore, you would need 10L of 0.5M Ca(OH)2 to neutralize 4L of 2.5M HCl.

Learn more about Neutralization of acids and bases