Question

A force of 45.0 N accelerates a 5.0-kg block at 5.6 m/s? along a horizontal surface. What’s the frictional force

Answer 1

Step-by-step explanation:

F = ma

= 5 kg * 5.6 m/s^2 = 28 N

the rest of the applied force or 45 N is used to overcome the frictional force 45 - 28 = 17 N Friction force