Question

Please help solve this by today

Answer 1

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of Line A. To get the slope of any straight line, we simply need two points off of it, let's use those two in the picture below.

`(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{2}-\stackrel{y1}{(-6)}}}{\underset{\textit{\large run}} {\underset{x_2}{7}-\underset{x_1}{(-7)}}} \implies \cfrac{2 +6}{7 +7} \implies \cfrac{ 8 }{ 14 } \implies \cfrac{4}{7}`

so we are really looking for the equation of a line whose slope is 4/7 and it passes through P(0 , 3)

`(\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{4}{7} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{4}{7}}(x-\stackrel{x_1}{0}) \\\\\\ y-3=\cfrac{4}{7}x\implies {\Large \begin{array}{llll} y=\cfrac{4}{7}+3 \end{array}}`