Question

In 2001, the population in a town was 12% more than it was in 2000. If the population was 23,690 in 2002, which

was 10% more than 2001, find the population in 2000.
The population in 2000 was
(Round to the nearest whole number.)

Answer 1

Approximately 19,233.

Explanation:

According to the problem statement, the population in 2001 was 12% more than the population in 2000. Therefore, the population in 2001 was 1.12P.

In 2002, the population was 10% more than the population in 2001. Therefore, the population in 2002 was 1.1(1.12P) = 1.232P.

We know that the population in 2002 was 23,690. Therefore, we can write the following equation:

1.232P = 23,690

Solving for P, we get:

P = 23,690 / 1.232 ≈ 19,233

Therefore, the population in 2000 was approximately 19,233.