Question

Third-degree, with zeros of −3 , −2 , and 1 , and passes through the point (4,6) .

Answer 1

Explanation:

From the zeros given:

f(x) = a ( x+3)(x+2)(x-1)

given when x = 4 then y = 6

f(4) = 6 = a ( 126) shows a = 1/21

f(x) = 1/21 ( (x+3)(x+2)(x-1)