Question

4x^2+98=0 quadratics

Answer 1

`x=+(7)/(√(2))i, \ -(7)/(√(2))i`

Explanation:

`\sf \rightarrow 4x^2+98=0`

`\sf \rightarrow 4x^2= -98`

`\sf \rightarrow x^2= -98/4 = -49/2`

`\sf \rightarrow x=\pm\sqrt{-(49)/(2)}`

• √-1 = i

`\sf \rightarrow x=\pm(7)/(√(2))i`

`\sf \rightarrow x=+(7)/(√(2))i, \ -(7)/(√(2))i`