Question

If 5.50 g of the unknown compound contained 0.183 mol of C and 0.367 mol of H, how many moles of oxygen, O , were in the sample?

Answer 1

0.183 mol O

Step-by-step explanation:

Convert moles of C and H to grams:

Grams of C = 0.183 mol * 12 g/mol = 2.196 g

Grams of H = 0.367 mol * 1 g/mol = 0.367 g

Subtract grams of C and H from the initial 5.50 grams to find grams of O:

Grams of O = 5.50 g - (2.196 g + 0.367 g) = 2.937 g

Convert grams of O to moles of O:

Moles of O = 2.937 g / 16 g/mol

Finally, Moles of O ≈ 0.183 mol.