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Determine the quantity in moles of Ag that are in 29.9 grams of Ag₂O.

asked
User Kerisa
by
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1 Answer

4 votes

Step-by-step explanation:

Every mole of Ag2 O has TWO moles of Ag in it .

Find number of moles of Ag2 O in 29.9 grams

Mole weight of Ag2 O 2 X 107.87 + 15.999 = 231.739 gm / mole

29.9 gm / 231.739 gm / mole = .129 moles of Ag2 O

Remember there are TWICE as many moles of Ag = .258 moles

answered
User Jherran
by
8.4k points
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