asked 185k views
4 votes
What is the product of (4+3i)(4-3i)

1 Answer

5 votes

Answer:


(4+3i)(4-3i)\\=4^2-(3i)^2\\=16-(3^2i^2)\\=16-[9(-1)]\ \ \ [\ i^2=-1\ ]\\=16-(-9)\\=16+9\\=25

answered
User Vardiak
by
8.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.