Question

A box contains 4 equal-sized cards labeled 1, 3, 5, and 7. Tim will select one card from the box.

Part A
What is the probability that Tim will select a card labeled 4? Enter an integer.
Part B
What is the probability that Tim will select a card labeled with a number less than 6? Enter a fraction.
Part C
What is the probability that Tim will select a card labeled with an odd number. Enter an integer.

Answer 1

Part A:

The probability that Tim will select a card labeled 4 is 0 because there is no card labeled 4 in the box.

Part B:

To find the probability that Tim will select a card labeled with a number less than 6, we need to calculate the number of favorable outcomes (cards labeled 1, 3, and 5) and divide it by the total number of possible outcomes (4 cards in total).

Probability = (Number of Favorable Outcomes) / (Total Number of Possible Outcomes)

Probability = 3 (favorable outcomes) / 4 (total possible outcomes) = 3/4

Part B: The probability that Tim will select a card labeled with a number less than 6 is 3/4.

Part C:

To find the probability that Tim will select a card labeled with an odd number, we count the number of favorable outcomes (cards labeled 1, 3, and 5) and divide it by the total number of possible outcomes (4 cards in total).

Probability = (Number of Favorable Outcomes) / (Total Number of Possible Outcomes)

Probability = 3 (favorable outcomes) / 4 (total possible outcomes) = 3/4

Part C: The probability that Tim will select a card labeled with an odd number is 3/4.

Explanation: