Question

If 38.2 ml of a 0.163 M NaOH solution is required to neutralize 35.0 ml of a solution of H2SO4 what is the molarity of the H2SO4 solution

Answer 1

The molarity of the H2SO4 solution is approximately 0.178 M.

Step-by-step explanation:

To find the molarity (M) of the H2SO4 solution, you can use the concept of stoichiometry and the equation:

M1V1 = M2V2

Where:

M1 is the molarity of the first solution (NaOH solution)

V1 is the volume of the first solution used (in liters)

M2 is the molarity of the second solution (H2SO4 solution)

V2 is the volume of the second solution used (in liters)

Given:

M1 (NaOH solution) = 0.163 M

V1 (NaOH solution) = 38.2 ml = 0.0382 L

V2 (H2SO4 solution) = 35.0 ml = 0.0350 L

Now, you can rearrange the formula to solve for M2 (molarity of H2SO4 solution):

M2 = (M1 * V1) / V2

M2 = (0.163 M * 0.0382 L) / 0.0350 L

M2 ≈ 0.178 M

So, the molarity of the H2SO4 solution is approximately 0.178 M.