Question

1) A force of 28 N stretches a very light ideal

spring 0.71 m from equilibrium. What is the
force constant (spring constant) of the spring?
A) 39 N/m
B) 22 N/m
C) 46 N/m
D) 31 N/m

Answer 1

Answer: A 39 N/m

Step-by-step explanation:

`F=-kx` Where k is the spring constant and x is the distortion (displacement from equilibrium). The negative will just mean the spring force is in the opposite direction of the distortion. For this problem, we can ignore that since we aren't worried about direction.

We plug in 28= k (0.71)

solve for k and we get 39 N/m