Question

in a half wave rectification process; when no load was connected the output was observed to be 220 v and when a load of 10 kq was connected the output was 210. what is the % regulation of the rectifier? 0.047 0.0454 0.029 0.0499

Answer 1

None of the answer choices provided exactly matches this value, but the closest one is 0.047.

Step-by-step explanation:

The percent regulation of a rectifier is calculated using the following formula:

Percent Regulation = [(No-Load Voltage - Full-Load Voltage) / Full-Load Voltage] * 100%

Given the following information:

No-Load Voltage = 220 V

Full-Load Voltage = 210 V

Let's calculate the percent regulation:

Percent Regulation = [(220 V - 210 V) / 210 V] * 100% = (10 V / 210 V) * 100% ≈ 4.76%

Rounding to two decimal places, the percent regulation is approximately 4.76%.

None of the answer choices provided exactly matches this value, but the closest one is 0.047.

So, the closest choice to the calculated percent regulation is 0.047.