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D/dx(10 csc 4x-ln 8x^11)

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D/dx(10 csc 4x-ln 8x^11)

asked Aug 20, 2024 6.5k views

3 votes

D/dx(10 csc 4x-ln 8x^11)

Mathematics
college

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1 Answer

5 votes

Answer:

Explanation:

d/dx(10 csc 4x-ln 8x^11) = -40csc(4x)cot(4x) - 88x^-1

Here, csc and cot are the cosecant and cotangent functions, respectively.

Jesse Jiang answered Aug 24, 2024

7.8k points

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