Question

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Answer 1

+5 and -5

`6 {x}^(2) = 150 \\ {x}^(2) = (150)/(6) \\ {x}^(2) = 25 \\ x = √(25 \\ ) \\ x = + 5 \: or \: x = - 5`

Answer 2

>>>
`\sf{x = \boxed{5} \: and \: \boxed{ - 5}}`

Explanation:

Given that ,

• Equation : 6x² = 150

We have to find ,

• Value of x

Solution :

`\longmapsto \: \: \: \sf{6x {}^(2) = 150 }`

Step 1 : Dividing both sides with 6 :

`\longmapsto \: \: \: \sf{ \frac{ \cancel{6}x {}^(2) }{ \cancel{6}}= \cancel{ (150 )/(6)}}`

We get ,

`\longmapsto \: \: \: \sf{x {}^(2) = 25 }`

Step 2 : Taking square root on both sides :

`\longmapsto \: \: \: \sf{ \sqrt{ x {}^(2)} = √( 25) }`

We have ,

`\longmapsto \: \: \: \sf{x = \pm √(25) }`

`\longmapsto \: \: \: \underline{ \boxed{\sf{ \bold{x = \pm \: 5 }}}} \: \: \: \bigstar`

• Therefore , value of x are " +5 and -5 "

Verification :-

#When x = 5 :

• 6x² = 150

• 6(5)² = 150

• 6 × 25 = 150

• 150 = 150

• LHS = RHS

• Hence, Verified

#When x = -5 :

• 6x² = 150

• 6(-5)² = 150

• 6 × 25 = 150

• 150 = 150

• LHS = RHS

• Hence, Verified

Therefore , our answer is correct

• Hope, it'll help you!! :)