Answer:When a mixture containing 33.0 g each of NH4Cl and Ca(OH)2 is heated, approximately 10.50 grams of NH3 will form. This is determined by the balanced chemical equation, which shows that 2 moles of NH4Cl react to form 2 moles of NH3. By calculating the number of moles of NH4Cl in the mixture (0.617 mol), we can conclude that the same number of moles of NH3 will be formed. Multiplying this by the molar mass of NH3 (17.03 g/mol) gives us the mass of NH3 formed, which is approximately 10.50 grams.