Question

Find a point slope form for the line with slope 1/5 and passing through the point (-8,-4).

Answer 1

`(\stackrel{x_1}{-8}~,~\stackrel{y_1}{-4})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{5} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{\cfrac{1}{5}}(x-\stackrel{x_1}{(-8)}) \implies y +4 = \cfrac{1}{5} ( x +8)`