Question

what is the stopping potential when for the emitted electrons when this photoelectrode is exposed to radiation of frequency 1200 thz? give your answer in v.

Answer 1

The stopping potential for emitted electrons when the photoelectrode is exposed to radiation of frequency 1200 THz is \( V = 3.18 \, V \).

Step-by-step explanation:

When light falls on a photoelectric material, electrons are emitted with kinetic energy determined by the energy of the incident photons. The stopping potential
`(\( V \))` is the minimum potential that must be applied to prevent these emitted electrons from reaching the anode. The relationship between the stopping potential, frequency of incident light (\( f \)), and Planck's constant
`(\( h \))` is given by the equation
`\( V = (hf)/(e) \), where \( e \) is` the elementary charge.

In this case, the frequency of the incident radiation is given as 1200 THz. To find the stopping potential, we use the formula
`\( V = (hf)/(e) \).`Substituting the known values, with Planck's constant
`\( h \)`being approximately
`\( 6.63 * 10^(-34) \, J \cdot s \)`and the elementary charge
`\( e \) being \( 1.6 * 10^(-19) \, C \),` we get
`\( V = ((6.63 * 10^(-34) \, J \cdot s) * (1.2 * 10^(15) \, Hz))/(1.6 * 10^(-19) \, C) \).`

Solving this expression yields
`\( V = 3.18 \, V \)`. This means that a potential of 3.18 volts must be applied to stop the emitted electrons and collect them at the anode. The stopping potential is a crucial parameter in understanding the photoelectric effect, providing insights into the energy distribution of emitted electrons and confirming the quantized nature of light.