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Fine (fof) (x) using f(x)= x^2-5

Fine (fof) (x) using f(x)= x^2-5
asked 216k views
1 vote
Fine (fof) (x) using f(x)= x^2-5

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User Notoriousxl
by
7.6k points

1 Answer

1 vote

Answer:

f(x) = x² - 5

f(f(x)) = f(x² - 5) = (x² - 5)² - 5

= x⁴ - 10x² + 25 - 5

= x⁴ - 10x² + 20

answered
User Brad Gardner
by
8.9k points
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