Question

Find three consecutive odd numbers whose sum is 147.Hint. Let the required numbers be (2x+1), (2x+3) and (2x+5).​

Answer 1

x + x + 2 + x + 4 = 147

3x + 6 = 147

3x = 141

x = 47, so x + 2 = 49, and x + 4 = 51.

The numbers are 47, 49, and 51.