Question

What is the theoretical yield of SO3 produced by 8.96 g of S?

Answer 1

Answer: Theoretical yield of
`SO_3` produced by 8.96 g of S is 33.6 g

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} S=(8.96g)/(32g/mol)=0.28moles`

The balanced chemical equation is:

`2S+3O_2\rightarrow 2SO_3`

According to stoichiometry :

2 moles of
`S` produce = 3 moles of
`SO_3`

Thus 0.28 moles of
`S` will produce=
`(3)/(2)* 0.28=0.42moles` of
`SO_3`

Mass of
`SO_3=moles* {\text {Molar mass}}=0.42moles* 80g/mol=33.6g`

Thus theoretical yield of
`SO_3` produced by 8.96 g of S is 33.6 g