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The mass of magnesium ions in 1 kg of sea water is 1.3 g. The concentration in parts per million (ppm) is a 1.3x10^6 b 1.3x10^3 c 1.3x10^-3

1 Answer

2 votes

Answer:

To calculate the concentration in parts per million (ppm), you need to express the mass of magnesium ions (1.3 g) in relation to the total mass of the solution (1 kg of sea water), and then multiply by 1,000,000 (since 1 ppm is equivalent to 1/1,000,000).

Concentration (ppm) = (Mass of solute / Total mass of solution) * 1,000,000

Concentration (ppm) = (1.3 g / 1000 g) * 1,000,000

Concentration (ppm) = (1.3 / 1000) * 1,000,000

Concentration (ppm) = 1,300,000

So, the concentration of magnesium ions in 1 kg of sea water is 1.3 x 10^6 ppm.

The correct option is:

A) 1.3x10^6

Step-by-step explanation:

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User Eddyparkinson
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