Answer:
See below.
Step-by-step explanation:
To determine the electron pair geometry of Carbonothioyl dibromide, we need to first draw its Lewis structure:
Br Br
\ /
C=S
/
Br Br
Carbonothioyl dibromide has four electron groups around the central sulfur atom: two single bonds with the two bromine atoms, one double bond with the carbon atom, and one lone pair of electrons on the sulfur atom.
Using VSEPR theory, we can predict the electron pair geometry by considering both the bonding and the lone pairs of electrons. In this case, the electron pair geometry of Carbonothioyl dibromide is tetrahedral because it has four electron groups around the central sulfur atom.
However, the molecular geometry of Carbonothioyl dibromide is trigonal pyramidal due to the presence of one lone pair of electrons on the sulfur atom.