Question

Equation for a circle that has a center of -6, 5 and passes through the point -11, 3

Answer 1

(x + 6)² + (y - 5)² = r²(-11 + 6)² + (3 - 5)² = r² (-5)² + (-2)² = r² 25 + 4 = r² 29 = r²

Answer: (x + 6)² + (y - 5)² = 29