Question

You have been keeping track of the outside temperature for a class project.

At noon, the temperature was 80°F
.
At 5:00
p.m., the temperature was 64°F
.

What was the percent change between the temperature at noon and the temperature at 5:00
p.m.?

Answer 1

20%

Explanation:

80 - 64 = 16

16 ÷ 80 = 0.2

0.2 × 100 = 20%