Question

Write an equation in slope-intercept form of the line that passes through the given point and parallel to the given line. (-2,-2); y=1/5x+9 ASAP PLS HELP

Answer 1

Explanation:

`m=(1)/(5)` (gradient same as line
`y=(1)/(5) x+9`)

Equation of line in point-slope form
`y-y_1=m(x-x_1)`:

`y-(-2)=(1)/(5) (x-(-2))` ( used
`m=(1)/(5)`, point (-2,-2) )

`y+2=(1)/(5) (x+2)`

`5y+10=x+2` (multiplied both sides by 5)

`5y=x-8` (subtracted 10 from both sides)

`y=(1)/(5) x-(8)/(5)` (divided both sides by 5)

Solution: Equation in slope-intercept form is

`y=(1)/(5) x-(8)/(5)`